An electric kettle for use on a 230 V supply is rated 3000 W. For safe working, the cable connected to it should be able to carry at least:
(a) 2 A
(b) 5 A
(c) 10 A
(d) 15 A
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Solution
(d) 15 A
Current drawn by the kettle, I = `I=P/V=3000/230=13A`
So the cable should be able to carry more current than this and hence the answer is 15 A
Concept: Electric Power
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