Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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An Electric Field → E = ( → I 20 + → J 30 ) N C − 1 Exists in Space. If the Potential at the Origin is Taken to Be Zero, Find the Potential at (2 M, 2 M). - Physics

Numerical

An electric field  \[\vec{E}  = ( \vec{i} 20 +  \vec{j} 30)   {NC}^{- 1}\]  exists in space. If the potential at the origin is taken to be zero, find the potential at (2 m, 2 m).

 
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Solution

Given:

\[\vec{E}  = ( \vec{i} 20 +  \vec{j} 30)  \] N/C 

\[\vec{r}  = (2 \vec{i}  + 2 \vec{j} )\]

So,

\[V =  -  \vec{E}  .  \vec{r}\]

\[\Rightarrow V =  - ( \vec{i} 20 + 30 \vec{j} ) .   (2 \vec{i}  + 2 \vec{j} )\] 

\[ \Rightarrow V =  - (2 \times 20 + 2 \times 30) =  - 100\] V

Concept: Electric Field - Electric Field Due to a System of Charges
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 7 Electric Field and Potential
Q 58 | Page 123
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