Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

# An Electric Field → E = ( → I 20 + → J 30 ) N C − 1 Exists in Space. If the Potential at the Origin is Taken to Be Zero, Find the Potential at (2 M, 2 M). - Physics

Numerical

An electric field  $\vec{E} = ( \vec{i} 20 + \vec{j} 30) {NC}^{- 1}$  exists in space. If the potential at the origin is taken to be zero, find the potential at (2 m, 2 m).

#### Solution

Given:

$\vec{E} = ( \vec{i} 20 + \vec{j} 30)$ N/C

$\vec{r} = (2 \vec{i} + 2 \vec{j} )$

So,

$V = - \vec{E} . \vec{r}$

$\Rightarrow V = - ( \vec{i} 20 + 30 \vec{j} ) . (2 \vec{i} + 2 \vec{j} )$

$\Rightarrow V = - (2 \times 20 + 2 \times 30) = - 100$ V

Concept: Electric Field - Electric Field Due to a System of Charges
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 7 Electric Field and Potential
Q 58 | Page 123