Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
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An Athlete Takes 2.0 S to Reach His Maximum Speed of 18.0 Km/H. What is the Magnitude of this Average Acceleration. - Physics

Short Note

An athlete takes 2.0 s to reach his maximum speed of 18.0 km/h. What is the magnitude of this average acceleration.

 
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Solution

Initial velocity, u = 0         
Final velocity, v = 18 km/h = 5 m/s
Time interval, t = 2 s
Using

\[v = u + at\] , we get:

\[\text{ Acceleration } = a_{av} = \frac{\left( v - u \right)}{2} = \frac{5}{2} = 2 . 5 \text{ m} / s^2\]

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APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 3 Rest and Motion: Kinematics
Q 5 | Page 51
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