# An Arc Subtends an Angle of 90° at the Centre of the Circle of the Radius 14 Cm. Write the Area of Minor Sector Thus Formed in Terms of π. - Mathematics

Sum

An arc subtends an angle of 90° at the centre of the circle of the radius 14 cm. Write the area of minor sector thus formed in terms of π.

#### Solution

We have given an angle subtended by an arc at the centre of the circle and radius of the circle.

r=14 cm

θ=90°

Now we will find the area of the minor sector.

Area of the minor sector =θ/360xxpir^2

Substituting the values we get,

Area of the minor sector = 90/360xxpixx14^2.......(1)

Now we will simplify the equation (1) as below,

Area of the minor sector =1/4xxpixx14^2

"Area of the minor sector" =1/4xxpixx14xx14

"Area of the minor sector" =pixx7xx7

Area of the minor sector = 49 pi

Therefore, area of the minor sector is 49 pi cm^2

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#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 13 Areas Related to Circles
Q 13 | Page 68