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An Arc Subtends an Angle of 90° at the Centre of the Circle of the Radius 14 Cm. Write the Area of Minor Sector Thus Formed in Terms of π. - Mathematics

Sum

An arc subtends an angle of 90° at the centre of the circle of the radius 14 cm. Write the area of minor sector thus formed in terms of π.

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Solution

We have given an angle subtended by an arc at the centre of the circle and radius of the circle.

`r=14 cm`

`θ=90°`

Now we will find the area of the minor sector.

Area of the minor sector =`θ/360xxpir^2`

Substituting the values we get, 

Area of the minor sector = `90/360xxpixx14^2`.......(1)

Now we will simplify the equation (1) as below,

Area of the minor sector `=1/4xxpixx14^2`

`"Area of the minor sector" =1/4xxpixx14xx14`

`"Area of the minor sector" =pixx7xx7`

Area of the minor sector = `49 pi`

Therefore, area of the minor sector is `49 pi cm^2`

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 13 Areas Related to Circles
Q 13 | Page 68
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