An alternative voltage given by V = 140 sin 314t is connected across a pure resistor of 50 Ω. Find
(i) The frequency of the source.
(ii) The rms current through the resistor.
Given V = 140 sin 314t, R = 50Ω
(1) Comparing with V = V0 sin ωt
Thus, V0 = 140 V
ω = 314
2πν = 314
`v = 314/(2 xx3.14) Hz = 50Hz`
(2) `V_(rms) = V_0/sqrt2 = 140/sqrt2 = 98.99V`
`I_(rms) = V_(rms)/R = 98.99/50 = 1.97A`