Share
Notifications

View all notifications

An Alternative Voltage Given by V = 140 Sin 314t is Connected Across a Pure Resistor of 50 ω. Find (I) the Frequency of the Source. (Ii) the Rms Current Through the Resistor. - Physics

Login
Create free account


      Forgot password?
ConceptReactance and Impedance

Question

An alternative voltage given by V = 140 sin 314t is connected across a pure resistor of 50 Ω. Find

(i) The frequency of the source.

(ii) The rms current through the resistor.

Solution

Given V = 140 sin 314t, R = 50Ω

(1) Comparing with V = V0 sin ωt

Thus, V0 = 140 V

ω = 314

2πν = 314

`v = 314/(2 xx3.14) Hz = 50Hz`

(2) `V_(rms) = V_0/sqrt2 = 140/sqrt2 = 98.99V`

`I_(rms) = V_(rms)/R = 98.99/50 = 1.97A`

  Is there an error in this question or solution?

Video TutorialsVIEW ALL [2]

Solution An Alternative Voltage Given by V = 140 Sin 314t is Connected Across a Pure Resistor of 50 ω. Find (I) the Frequency of the Source. (Ii) the Rms Current Through the Resistor. Concept: Reactance and Impedance.
S
View in app×