An alkyl iodide on refluxing with aqueous KOH solution gave isopropyl alcohol. The structure of alkyl iodide could be: - Chemistry

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MCQ

An alkyl iodide on refluxing with aqueous KOH solution gave isopropyl alcohol. The structure of alkyl iodide could be:

Options

  • \[\ce{CH3 - CH2 - CH2 - I}\]

  • \[\begin{array}{cc}
    \ce{CH3 - CH - CH3}\\
    |\phantom{..}\\
    \ce{I}\phantom{..}
    \end{array}\]

  • \[\ce{CH3 - CH2 - CH2 - CH2 - I}\]

  • \[\begin{array}{cc}
    \phantom{...}\ce{CH3}\\
    |\\
    \ce{CH3 - C - CH3}\\
    |\\
    \ce{I}
    \end{array}\]

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Solution

\[\begin{array}{cc}
\ce{CH3 - CH - CH3}\\
|\phantom{..}\\
\ce{I}\phantom{..}
\end{array}\]

Explanation:

Hydrolysis of an alkyl halide with aqueous KOH yields the corresponding alcohol. A primary alkyl halide becomes primary alcohol, while a secondary alkyl halide becomes secondary alcohol. As a result, when isopropyl alcohol is produced by alkaline hydrolysis of an alkyl iodide, the alkyl iodide must be isopropyl iodide.

Concept: Methods of Preparation of Alkyl Halides
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