Answer 1

Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft, `v = 900 km/h = 900 xx 5/18 = 250 m/s`

Centripetal acceleration, `a_c = v^2/r`

`=(250)^2/1000 = 62.5 m/s^2`

Acceleration due to gravity, g = 9.8 m/s²

`a_c/g = 62.5/9.8 = 6.38`

`a_c =6.38g`

Answer 2

Here `r = 1 km = 10^3 m, v = 900 km h^(-t) = 900 xx 5/18 = 250 ms^(-1)`

Centripetal accelration = `a_c =v^2/r = (250)^2/10^3 = 62.5 ms^(-2)`

Now `a_c/g = 62.5/9.8 = 6.38`