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An Aircraft Executes a Horizontal Loop of Radius 1.00 Km with a Steady Speed of 900 Km/H. Compare Its Centripetal Acceleration with the Acceleration Due to Gravity. - Physics

An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.

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Solution 1

Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft, `v = 900 km/h = 900 xx 5/18 = 250 m/s`

Centripetal acceleration, `a_c = v^2/r`

`=(250)^2/1000 = 62.5 m/s^2`

Acceleration due to gravity, g = 9.8 m/s2

`a_c/g = 62.5/9.8 = 6.38`

`a_c =6.38g`

Solution 2

Here `r = 1 km = 10^3 m, v = 900 km h^(-t) = 900 xx 5/18 = 250 ms^(-1)`

Centripetal accelration = `a_c =v^2/r = (250)^2/10^3 = 62.5 ms^(-2)`

Now `a_c/g = 62.5/9.8 = 6.38`

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APPEARS IN

NCERT Class 11 Physics Textbook
Chapter 4 Motion in a Plane
Q 18 | Page 87
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