# An Aircraft Executes a Horizontal Loop of Radius 1.00 Km with a Steady Speed of 900 Km/H. Compare Its Centripetal Acceleration with the Acceleration Due to Gravity. - Physics

An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.

#### Solution 1

Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft, v = 900 km/h = 900 xx 5/18 = 250 m/s

Centripetal acceleration, a_c = v^2/r

=(250)^2/1000 = 62.5 m/s^2

Acceleration due to gravity, g = 9.8 m/s2

a_c/g = 62.5/9.8 = 6.38

a_c =6.38g

#### Solution 2

Here r = 1 km = 10^3 m, v = 900 km h^(-t) = 900 xx 5/18 = 250 ms^(-1)

Centripetal accelration = a_c =v^2/r = (250)^2/10^3 = 62.5 ms^(-2)

Now a_c/g = 62.5/9.8 = 6.38

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#### APPEARS IN

NCERT Class 11 Physics Textbook
Chapter 4 Motion in a Plane
Q 18 | Page 87