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An Aeroplane is Flying Horizontally from West to East with a Velocity of 900 Km/Hour. - Physics

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Sum

An aeroplane is flying horizontally from west to east with a velocity of 900 km/hour. Calculate the potential difference developed between the ends of its wings having a span of 20 m. The horizontal component of the Earth's magnetic field is 5 × 10–4 T and the angle of dip is 30°.

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Solution

Potential difference developed between the ends of the wings e = Bl𝜈

Given Velocity v = 900km/hour = 250m/s

The horizontal component of the Earth’s magnetic field = 5× 10-4T

Wing span (l) = 20 m

The vertical component of Earth’s magnetic field

BV = BH tan δ

= 5×10−4 (tan 30° ) T

∴ The potential difference, e

= 5×10−4 ( tan 30° ) × 20 × 250

e = `(5 xx 10^-4 xx 20 xx 250)/sqrt3 = 1.44 "V"`

Concept: Induced e.m.f. and Induced Current
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