CBSE (Science) Class 11CBSE
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Solution for Draw the Cis and Trans Structures of Hex-2-ene. Which Isomer Will Have Higher B.P. and Why? - CBSE (Science) Class 11 - Chemistry

Login
Create free account


      Forgot password?

Question

Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

Solution 1

Hex-2-ene is represented as:

`CH_3 - CH =CH - CH_2 - CH_2 -CH_3`

Geometrical isomers of hex-2-ene are:

The dipole moment of cis-compound is a sum of the dipole moments of C–CH3 and C–CH2CH2CH3 bonds acting in the same direction.

The dipole moment of trans-compound is the resultant of the dipole moments of C–CH3 and C–CH2CH2CH3 bonds acting in opposite directions.

Hence, cis-isomer is more polar than trans-isomer. The higher the polarity, the greater is the intermolecular dipole-dipole interaction and the higher will be the boiling point. Hence, cis-isomer will have a higher boiling point than trans-isomer.

Solution 2

The structures of cis- and trans-isomer of hex-2-ene are:

The boiling point of a molecule depends upon dipole-dipole interactions. Since cis-isomer has higher dipole moment, therefore, it has higher boiling point.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Chemistry Textbook for Class 11 Part 2 (with solutions)
Chapter 12: Organic Chemistry - Some Basic Principles and Techniques
Q: 9 | Page no. 397
Solution for question: Draw the Cis and Trans Structures of Hex-2-ene. Which Isomer Will Have Higher B.P. and Why? concept: Alkenes - Isomerism. For the courses CBSE (Science), CBSE (Science)
S
View in app×