#### Question

Solve the following systems of equations:

x + y = 5xy

3x + 2y = 13xy

#### Solution

The given system of equation is

x + y = 5xy ....(i)

3x + 2y = 13xy ....(ii)

Multiplying equation (i) by 2 and equation (ii) by , we get

2x + 2y = 10xy ....(iii)

3x + 2y = 13xy ....(iv)

Subtracting equation (iii) from equation (iv), we get

3x - 2x = 13xy - 10xy

=> x = 3xy

`=> x/(3y) = y`

`=> y = 1/3`

Putting y = 1/3 in equation (i), we get

`x + y = 5 xx x xx 1/3`

`x + 1/3 = (5x)/3`

`=> 1/3 = (5x)/3 - x`

`=> 1/3 = (5x - 3x)/3`

=> 1 = 2x

=> 2x = 1

`=> x = 1/2`

Hence, solution of the given system of equations is `x = 1/2, y = 1/3`

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#### APPEARS IN

Solution Solve the Following Systems of Equations: X + Y = 5xy 3x + 2y = 13xy Concept: Algebraic Methods of Solving a Pair of Linear Equations - Substitution Method.