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Solve Each of the Following Systems of Equations by the Method of Cross-multiplication : `57/(X + Y) + 6/(X - Y) = 5` `38/(X + Y) + 21/(X - Y) = 9` - CBSE Class 10 - Mathematics

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Question

Solve each of the following systems of equations by the method of cross-multiplication :

`57/(x + y) + 6/(x - y) = 5`

`38/(x + y) + 21/(x - y) = 9`

Solution

Let `1/(x +y) = u and 1/(x -y ) = v` Then the given system of equations become

`57u + 6v = 5 => 57u + 6v - 5 = 0`

``38u + 21v = 9 => 38u + 21v - 9 = 0`

Here

`a_1 = 57, b_1 = 6, c_1 = -5`

`a_2 = 38, b_2 = 21, c_2 = -9`

By cross multiplication, we have

`=> u/(-54 + 105) = (-v)/(-513 + 190) = 1/(1193 - 228)`

`=> u/51 = (-v)/(-323) = 1/969`

`=> u/51 = v/323 = 1/969`

Now

`u/51= 1/969`

`=> u = 51/969`

`=> u = 1/19`

And

`v/(323) = 1/969`

`=> v = 323/969`

`=> v = 1/3`

Now

`u = 1/(x + y)``

`=> 1/(x + y)  =1/ 19`

`=>x + y = 19` ....(i)

And

`v = 1/(x - y)` 

`=> 1/(x -y) = 1/3`

=> x - y = 3 ...(ii)

Now adding eq i and ii

we get x = 11

And after substituting te value x in eq (ii)

we get y = 8

Hence  the value oof x = 11 and y = 8

  Is there an error in this question or solution?

APPEARS IN

Solution Solve Each of the Following Systems of Equations by the Method of Cross-multiplication : `57/(X + Y) + 6/(X - Y) = 5` `38/(X + Y) + 21/(X - Y) = 9` Concept: Algebraic Methods of Solving a Pair of Linear Equations - Cross - Multiplication Method.
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