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∠Acd is an Exterior Angle of δ Abc. If ∠B = 40o, ∠A = 70o Find ∠Acd. - Geometry

∠ACD is an exterior angle of Δ ABC. If ∠B = 40o, ∠A = 70o find ∠ACD.

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Solution

∠ ACD = ∠ B + ∠ A .............. (theorem of remote interior angle)
= 40 + 70
= 110˚

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