&ang;ACD is an exterior angle of Δ ABC. If &ang;B = 40o, &ang;A = 70o find &ang;ACD.

&ang; ACD = &ang; B + &ang; A .............. (theorem of remote interior angle)= 40 + 70= 110˚

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∠Acd is an Exterior Angle of δ Abc. If ∠B = 40o, ∠A = 70o Find ∠Acd. - Geometry

∠ACD is an exterior angle of Δ ABC. If ∠B = 40o, ∠A = 70o find ∠ACD.

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Solution

∠ ACD = ∠ B + ∠ A .............. (theorem of remote interior angle)
= 40 + 70
= 110˚

Concept: Trigonometric Ratios of Complementary Angles

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∠Acd is an Exterior Angle of δ Abc. If ∠B = 40o, ∠A = 70o Find ∠Acd. - Geometry

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