Answer 1

Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide:

Due to the +I effect of −CH₃ group, methylamine is more basic than water. Therefore, in water, methylamine produces OH⁻ ions by accepting H⁺ ions from water.

Ferric chloride (FeCl₃) dissociates in water to form Fe³⁺ and Cl⁻ ions.

`FeCl_3 -> Fe^(3+) + 3Cl^(-)`

Then, OH⁻ ion reacts with Fe³⁺ ion to form a precipitate of hydrated ferric oxide.

`2Fe^(3+) + 6OH^(-) -> Fe_2O_3. 3H_2O`

                                        Hydrated

                                       ferric oxide

 

Answer 2

Methylamine being more basic than water, accepts a proton from water liberating OH^– ions,

These `OH^(-)` ions combine with `Fe^(3+)` ions present in `H_2O` to form brown precipitate of hydrate ferric oxide.

`FeCl_3 -> Fe^(3+) + 3Cl^(-)`

`2Fe^(3+) + 6OH^(-) ->`

`2Fe(OH)_3 or Fe_2O_3. 3H_2O`

                  (Brown ppt)