# Abcd is a Trapezium in Which Ab || Dc. If Ar (δAbd) = 24 Cm2 and Ab = 8 Cm, Then Height of δAbc is - Mathematics

MCQ

ABCD is a trapezium in which AB || DC. If ar (ΔABD) = 24 cm2 and AB = 8 cm, then height of ΔABC is

•  3 cm

• 4 cm

•  6 cm

•  8 cm

#### Solution

Given: (1) ABCD is a trapezium, with parallel sides AB and DC

(2) Area of ΔADB = 24 cm2

(3) AB = 8 cm

To find: Height of ΔABC.

Calculation: We know that ,” two triangles with the same base and between the same parallels are equal in area.”

Here we can see that, ΔADB and ΔACB are on the same base AB.

Hence,

Area of ΔACB = Area of ΔADB

Area of ΔACB = 24

1/2 (8 xx h) =24

h = (24 xx 2)/8

h = 6 cm

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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 14 Areas of Parallelograms and Triangles
Q 16 | Page 61