ABCD is a trapezium in which AB || DC. If ar (ΔABD) = 24 cm2 and AB = 8 cm, then height of ΔABC is
Given: (1) ABCD is a trapezium, with parallel sides AB and DC
(2) Area of ΔADB = 24 cm2
(3) AB = 8 cm
To find: Height of ΔABC.
Calculation: We know that ,” two triangles with the same base and between the same parallels are equal in area.”
Here we can see that, ΔADB and ΔACB are on the same base AB.
Area of ΔACB = Area of ΔADB
Area of ΔACB = 24
`1/2 (8 xx h) =24 `
`h = (24 xx 2)/8`
h = 6 cm