Answer 1

Given : Rhombus ABCD in which ∠BCA = 35°

To find : ∠ADC

Proof : AD || BC

∠DAC = ∠BCA (Alternate ∠s)

But ∠BCA = 35° (Given)

∠DAC = 35°

But ∠DAC = ∠ACD ( AD = CD) & ∠DAC +∠ACD + ∠ADC = 180°

35°+ 35° + ∠ADC = 180°

∠ADC = 180° – 70° = 110°

Hence ∠ADC = 110°