ABC is an isosceles triangle with AB = AC. Drawn AP ⊥ BC to show that ∠B = ∠C.
In ΔAPB and ΔAPC,
∠APB = ∠APC (Each 90º)
AB =AC (Given)
AP = AP (Common)
∴ ΔAPB ≅ ΔAPC (Using RHS congruence rule)
⇒ ∠B = ∠C (By using CPCT)
Concept: Some More Criteria for Congruence of Triangles
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- Some More Criteria for Congruence of Triangles