AB is a chord of a circle with centre O and radius 4 cm. AB is of length 4 cm. Find the area of the sector of the circle formed by chord AB.
We have to find the area of the sector AOB formed by the chord AB.
We have `OA=4 cm and AB=4 cm. So,`
`= 4/2 cm`
`= 2 cm`
Let ∠AOB=2θ. then,
In ΔOLA, We have
`θ = sin^-1 1/2`
Now, using the value of`∠AOB` and r we will find the area of sector AOB,
`A=θ/(360°) xx pir^2`
=` (60°)/(360°)xx pixx4xx4 cm^2`
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