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A wire when bent in the form of a square encloses an area of 484cm^{2}. If the same wire is bent into the form of a circle, find the area of the circle.

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#### Solution

The side of a square whose area is 484cm^{2}

= `sqrt(484)`

= 22cm

⇒ The perimeter of the square = 4 x 22cm

The Circumference of a Circle with radius r = 2πr

Here,

2πr = 4 x 22cm

⇒ r = `(88)/(2pi)`

= `(88 xx 7)/(2 xx 22)`

= 14cm

The Area of a Circle with radius r = πr^{2}

The Area of a Circle with radius 14 = π(14)^{2}

= `(22)/(7) xx (14)^2`

= 22 x 2 x 14

= 616cm^{2}.

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