# A Wire, When Bent in the Form of a Square Encloses an Area of 484 Cm2. Find : (I) One Side of the Square ; (Ii) Length of the Wire ; (Iii) the Largest Area Enclosed; If the Same Wire - Mathematics

Sum

A wire, when bent in the form of a square encloses an area of 484 cm2. Find :
(i) one side of the square ;
(ii) length of the wire ;
(iii) the largest area enclosed; if the same wire is bent to form a circle.

#### Solution

(i)

Area of Square = 484 cm2
Side of Square = sqrt("Area") = sqrt484 = 22 cm
(ii)

Perimeter, i.e. length of wire = 4 x 22 = 88 cm
(iii)

Circumference of circle = 88 cm
2πr = 88

2 xx 22/7 xx r = 88

r = (88 xx 7)/(2 xx 22)

r = 14 cm

∴ The largest area enclosed = pir^2

= 22/7 xx 14 xx 14

= 616 cm2

Hence (i) 22 cm (ii) 88 cm (iii) 616 cm2

Concept: Perimeter of Squares
Is there an error in this question or solution?

#### APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 20 Area of a Trapezium and a Polygon
Exercise 20 (D) | Q 10 | Page 234