Sum

A well is dug 20 m deep and it has a diameter of 7 m. The earth which is so dug out is spread out on a rectangular plot 22 m long and 14 m broad. What is the height of the platform so formed?

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#### Solution

Height of the well = h m = 20 m

Diameter of the well = d m =7 m

Radius of the well = r m = 3.5 m

Volume of the well = πr^{2}h = __22__(3.5)^{2}(20 ) m^{3}= 770 m^{3}

7

Volume of the well = Volume of the rectangular plot

Length of the rectangular plot = 22 m

Breadth of the rectangular plot =14 m

Volume of the rectangular plot = 770 m^{3} = (Length x Breadth x Height) of the rectangular plot \[\text{ Height }= \frac{770}{22 \times 14} = 2 . 5 m\]

Thus, the height of the platform is 2.5 m.

Concept: Surface Area of Cylinder

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