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A Wave Pulse Passing on a String with a Speed of 40 Cm S−1 in the Negative X-direction Has Its Maximum at X = 0 at T = 0. Where Will this Maximum Be Located at T = 5 S? - Physics

Short Note

A wave pulse passing on a string with a speed of 40 cm s−1 in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5 s?

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Solution


Given,
Speed of the wave pulse passing on a string in the negative x-direction = 40 cms−1
As the speed of the wave is constant, the location of the maximum after 5 s will be
s = v × t
   = 40 × 5
   = 200 cm (along the negative x-axis)
Therefore, the required maximum will be located after x = −2 m.

Concept: Speed of Wave Motion
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APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 15 Wave Motion and Waves on a String
Q 1 | Page 323
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