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Sum
A tunnel through a mountain for a four-lane highway is to have a elliptical opening. The total width of the highway (not the opening) is to be 16 m, and the height at the edge of the road must be sufficient for a truck 4 m high to clear if the highest point of the opening is to be 5 m approximately. How wide must the opening be?
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Solution
Let the equation of the ellipse be
`x^2/"a"^2 + y^2/"b"^2` = 1
Length of semi minor axis b = 5
i.e., `x^2/"a"^2 + y^2/5^2` = 1
Let BB’ be the road width and AA’ be the endpoints of the opening of the tunnel.
Let CB = 8, BD = 4
∴ D is (8, 4) lies on the ellipse
`8^2/"a"^2 + 4^2/5^2` = 1
⇒ a2 = `25/9 xx 64`
⇒ a = `40/3`
The width AA’ = 2a
= `80/3`
= 26.66 m
The required width is 26.66 m
Concept: Real Life Applications of Conics
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