Sum

A tuning fork produces 4 beats per second with another tuning fork of frequency 256 Hz. The first one is now loaded with a little wax and the beat frequency is found to increase to 6 per second. What was the original frequency of the tuning fork?

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#### Solution

Frequency of tuning fork A : \[n_1\] = 256 Hz

No. of beats/second *m* = 4

Frequency of second fork B : \[n_2\] =?

\[n_2 = n_1 \pm m\]

\[\Rightarrow\] \[n_2 = 256 \pm 4\]

\[\Rightarrow\] \[n_2\] = 260 Hz or 252 Hz

Now, as it is loaded with wax, its frequency will decrease.

As it produces 6 beats per second, the original frequency must be 252 Hz.

260 Hz is not possible because on decreasing the frequency, the beats per second should decrease, which is not possible.

Concept: Wave Motion

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