Answer 1

We have to find the distance travelled by the train. We have the following information given,
So, initial velocity, (u) = 20 m/s
Acceleration, (a) = 0.5 m/s²
Time taken, (t) = 30 s
We can calculate the distance travelled by using the 2^nd equation of motion,
`s = ut + 1/2at^2`
Put the values in above equation to find the distance travelled by the train,
`(s) = 20(30) + 1/2(0.5)(30)^2`
= (600 + 225) m
= 825 m