A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45°. Then the height (in meters) of the tower is
Let AB be the tower and C be the point on the ground 25 m away from the foot of the
tower such that ∠ACB = 45°.
In right ΔABC:
`tan 45 ^@=(AB)/(BC)`
⇒ AB = 25 m
Thus, the height of the tower is 25 m.
The correct answer is C.