Share
Notifications

View all notifications
Advertisement

A Tower Stands Vertically on the Ground. from a Point on the Ground Which is 25 M Away from the Foot of the Tower, the Angle of Elevation of the Top of the Tower is Found to Be 45°. - Mathematics

Login
Create free account


      Forgot password?

Question

A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45°. Then the height (in meters) of the tower is

Options
  • A. `25sqrt2`

  • B. `25sqrt3`

  • C. 25

  • D. 12.5

Solution

Let AB be the tower and C be the point on the ground 25 m away from the foot of the

tower such that ∠ACB = 45°.

In right ΔABC:

`tan 45 ^@=(AB)/(BC)`

`rArr l=(AB)/25m`

⇒ AB = 25 m

Thus, the height of the tower is 25 m.

The correct answer is C.

  Is there an error in this question or solution?
Advertisement
Advertisement
A Tower Stands Vertically on the Ground. from a Point on the Ground Which is 25 M Away from the Foot of the Tower, the Angle of Elevation of the Top of the Tower is Found to Be 45°. Concept: Heights and Distances.
Advertisement
View in app×