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A Thin Conducting Spherical Shell of Radius R Has Charge Q Spread Uniformly Over Its Surface. Using Gauss’S Law, Derive an Expression for an Electric Field at a Point Outside the Shell. - Physics

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Question

A thin conducting spherical shell of radius R has charge Q spread uniformly over its surface. Using Gauss’s law, derive an expression for an electric field at a point outside the shell.

Solution

According to Gauss law,

`epsi_0EointdA=q`

Where,

q is the point charge

E is electric field due to the point charge

dA is a small area on the Gaussian surface at any distance and

`epsi_0` is the proportionality constant

For a spherical shell at distance r from the point charge, the integral `ointdA` is merely the sum of all differential of dA on the sphere.

Therefore, `oint dA =4pir^2`

`epsi_0E(4pir^2) = q`

or `,E = q/(epsi4pir^2)`

Therefore, for a thin conducting spherical shell of radius R and charge Q, spread uniformly over its surface, the electric field at any point outside the shell is

`E = Q/(e_0 4pir^2)`

Where r is the distance of the point from the centre of the shell.

`E = q/(4piepsi_0r^2)`

  Is there an error in this question or solution?
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A Thin Conducting Spherical Shell of Radius R Has Charge Q Spread Uniformly Over Its Surface. Using Gauss’S Law, Derive an Expression for an Electric Field at a Point Outside the Shell. Concept: Gauss’s Law.
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