# A Tea-packet Measures 10 Cm × 6 Cm × 4 Cm. How Many Such Tea-packets Can Be Placed in a Cardboard Box of Dimensions 50 Cm × 30 Cm × 0.2 M? - Mathematics

A tea-packet measures 10 cm × 6 cm × 4 cm. How many such tea-packets can be placed in a cardboard box of dimensions 50 cm × 30 cm × 0.2 m?

#### Solution

$\text { Dimension of a tea packet is 10 cm } \times 6 cm \times 4 cm .$

$\text { Volume of a tea packet = length } \times \text { br eadth } \times \text { height = } (10 \times 6 \times 4) {cm}^3 = 240 {cm}^3$

$\text { Also, it is given that the dimension of the cardboard box is 50 cm } \times 30 cm \times 0 . 2 m, i . e . , 50 cm \times 30 cm \times 20 cm ( \because 1 m = 100 cm)$

$\text { Volume of the cardboard box = length } \times \text { breadth } \times\text { height } = (50 \times 30 \times 20) {cm}^3 = 30000 {cm}^3$

$\therefore\text { The number of tea packets that can be placed inside the cardboard box } = \frac{\text { volume of the box }}{\text { volume of a tea packet }} = \frac{30000 {cm}^3}{240 {cm}^3} = 125$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.1 | Q 18 | Page 9