Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

A Tangent Galvanometer Shows a Deflection of 45° When 10 Ma of Current is Passed Through It. If the Horizontal Component of the Earth'S Magnetic Field is B H = 3.6 × 10 − 5 T a - Physics

Sum

A tangent galvanometer shows a deflection of 45° when 10 mA of current is passed through it. If the horizontal component of the earth's magnetic field is B_H = 3.6 xx 10^-5  "T" and radius of the coil is 10 cm, find the number of turns in the coil.

Solution

Given :
Horizontal component of Earth's magnetic field,B_H = 3.6 xx 10^-5  "T"

Deflection shown by the tangent galvanometer, θ = 45^circ

Current through the galvanometer, l = 10  "mA" = 10^-2  "A"

Radius of the coil, r = 10  "cm" = 0.1  "m"

Number of turns in the coil, n = ?

We know ,

B_H tan θ = (u_0 In)/(2r)

⇒ n = (B_H tan  \ θ  xx 2r)/(u_0I)

⇒ n = (3.6 xx 10^-5 xx 2 xx 1 xx 10^-1)/(4pi xx 10^-7 xx 10^-2)

⇒ n = 0.57332 xx 10^3 = 573

Is there an error in this question or solution?

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 14 Permanent Magnets
Q 16 | Page 278