A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11 - Mathematics

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A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11. Do you agree with this argument?

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Solution

Probability of each of these sums will not be 1/11 as these sums are not equally likely.

Concept: Probability - A Theoretical Approach

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Q 22.2 Q 22.1 Q 23

Chapter 15: Probability - Exercise 15.1 [Page 310]

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Chapter 15 Probability
Exercise 15.1 | Q 22.2 | Page 310

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A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11 - Mathematics

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A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11 - Mathematics

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