Answer 1

Height of the tower, s = 500 m

Velocity of sound, v = 340 m s⁻¹

Acceleration due to gravity, g = 10 m s⁻²

Initial velocity of the stone, u = 0 (since the stone is initially at rest)

Time taken by the stone to fall to the base of the tower, t₁

According to the second equation of motion:-

`s=ut_1+1/2"gt"_1^2`

`500=0xxt_1+1/2xx10xxt_1^2`

`t_1^2=100`

t₁ = 10 s

Now, time taken by the sound to reach the top from the base of the tower, `t_2=500/340-1.47s`

Therefore, the splash is heard at the top after time, t

Where, t = t₁ + t₂ = 10 + 1.47 = 11.47 s