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A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m s−2 and speed of sound = 340 m s−1. - Science

A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m s−2 and speed of sound = 340 m s−1.

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Solution

Height of the tower, s = 500 m

Velocity of sound, v = 340 m s−1

Acceleration due to gravity, g = 10 m s−2

Initial velocity of the stone, u = 0 (since the stone is initially at rest)

Time taken by the stone to fall to the base of the tower, t1

According to the second equation of motion:-

`s=ut_1+1/2"gt"_1^2`

`500=0xxt_1+1/2xx10xxt_1^2`

`t_1^2=100`

t1 = 10 s

Now, time taken by the sound to reach the top from the base of the tower, `t_2=500/340-1.47s`

Therefore, the splash is heard at the top after time, t

Where, t = t1 + t2 = 10 + 1.47 = 11.47 s

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APPEARS IN

NCERT Class 9 Science Textbook
Chapter 12 Sound
Q 13 | Page 174
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