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A Square Coil of Side 10 cm Consists of 20 Turns and Carries a Current of 12 A. the Coil is Suspended Vertically and the Normal to the Plane of the Coil Makes an Angle of 30º with the Direction of a Uniform Horizontal Magnetic Field of Magnitude 0.80 T. What is the Magnitude of Torque Experienced by the Coil? - Physics

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ConceptTorque on Current Loop, Magnetic Dipole Torque on a Rectangular Current Loop in a Uniform Magnetic Field

Question

A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30º with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?

Solution

Length of a side of the square coil, l = 10 cm = 0.1 m

Current flowing in the coil, I = 12 A

Number of turns on the coil, n = 20

Angle made by the plane of the coil with magnetic field, θ = 30°

Strength of magnetic field, B = 0.80 T

Magnitude of the magnetic torque experienced by the coil in the magnetic field is given by the relation,

τ = n BIA sinθ

Where,

A = Area of the square coil

l × l = 0.1 × 0.1 = 0.01 m2

∴ τ = 20 × 0.8 × 12 × 0.01 × sin30°

= 0.96 N m

Hence, the magnitude of the torque experienced by the coil is 0.96 N m.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 4: Moving Charges and Magnetism
Q: 9 | Page no. 169
Solution A Square Coil of Side 10 cm Consists of 20 Turns and Carries a Current of 12 A. the Coil is Suspended Vertically and the Normal to the Plane of the Coil Makes an Angle of 30º with the Direction of a Uniform Horizontal Magnetic Field of Magnitude 0.80 T. What is the Magnitude of Torque Experienced by the Coil? Concept: Torque on Current Loop, Magnetic Dipole - Torque on a Rectangular Current Loop in a Uniform Magnetic Field.
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