Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

# A Source Emits 45 Joules of Energy in 15 S. What is the Radiant Flux of the Source? - Physics

Sum

A source emits 45 joules of energy in 15 s. What is the radiant flux of the source?

#### Solution

Given,

Total energy emitted (E) = 45 J

Time (t) = 15 s

Radiant flux of the source is given by,

"Radiant Flux"="Total energy emitted"/"Time"

=45/15=3"W"

So, the radiant flux of the source is 3 W.

Concept: Light Process and Photometry
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 22 Photometry
Exercise | Q 1 | Page 455
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