Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

A Source Emits 45 Joules of Energy in 15 S. What is the Radiant Flux of the Source? - Physics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum

A source emits 45 joules of energy in 15 s. What is the radiant flux of the source?

Advertisement Remove all ads

Solution

Given,

Total energy emitted (E) = 45 J

Time (t) = 15 s

Radiant flux of the source is given by,

`"Radiant Flux"="Total energy emitted"/"Time"`

`=45/15=3"W"`

So, the radiant flux of the source is 3 W.

Concept: Light Process and Photometry
  Is there an error in this question or solution?

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 22 Photometry
Exercise | Q 1 | Page 455
Share
Notifications

View all notifications


      Forgot password?
View in app×