# A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is 3.75 cm. If the velocity of sound is 1500 m/s - Physics

Sum

A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is 3.75 cm. If the velocity of sound is 1500 m/s, find the frequency.

#### Solution

Distance between two successive nodes
(λ/2) = 3.75 cm = 3.75 × 10−2 m, v = 1500 m/s

n = v/λ

As λ/2 = 3.75 × 10−2 m

∴ λ = 7.5 × 10−2 m

From formula,

∴ n = 1500/(7.5xx10^-2)

∴ n = 200 × 102

∴ n = 20 × 103

∴ n = 20 kHz

Concept: Harmonics and Overtones
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#### APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 6 Superposition of Waves
Exercises | Q 11 | Page 157