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Sum

A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is 3.75 cm. If the velocity of sound is 1500 m/s, find the frequency.

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#### Solution

Distance between two successive nodes

`(λ/2)` = 3.75 cm = 3.75 × 10^{−2} m, v = 1500 m/s

n = `v/λ`

As `λ/2` = 3.75 × 10^{−2} m

∴ λ = 7.5 × 10^{−2} m

From formula,

∴ n = `1500/(7.5xx10^-2)`

∴ n = 200 × 10^{2}

∴ n = 20 × 10^{3}

∴ n = 20 kHz

Concept: Harmonics and Overtones

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