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A Solid is Composed of a Cylinder with Hemispherical Ends. If the Whole Length of the Solid is 104 Cm and the Radius of Each of the Hemispherical Ends is 7 Cm, Find the Cost of Polishing Its Surface at the Rate of Rs 10 per Dm2 . - Mathematics

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A solid is composed of a cylinder with hemispherical ends. If the whole length of the solid is 104 cm and the radius of each of the hemispherical ends is 7 cm, find the cost of polishing its surface at the rate of Rs 10 per dm2 .

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Solution

We have a solid composed of cylinder with hemispherical ends.

Radius of the two curved surfaces(r) = 7 cm

Height of cylinder is h.

Total height of the body(h + 2r) = 104 cm

So, total surface area is given by,

Total surface area = Curved surface area of cylinder +2(Curves surface area of hemisphere)

=`2pirh+2(2pir^2)`

= 2πr(h+2r)

=2(3.14)(7)(104) cm2

=4571.84 cm2

Change the units of curved surface area as,

Total surface area = `4571.87/100 dm^2`

= 45.7184 dm2

Cost of polishing the surface is Rs 10 per dm2.

So total cost,

= Rs(45.7184)(10)

= Rs 457.18

Concept: Concept of Surface Area, Volume, and Capacity
  Is there an error in this question or solution?

APPEARS IN

RD Sharma Class 10 Maths
Chapter 14 Surface Areas and Volumes
Exercise 14.2 | Q 14 | Page 61
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