Answer 1

Given:

Length of solenoid, l = 3.142m

Diameter, d = 5.0cm = 5 × 10^-2m

Radius, r = 2.5cm = 2.5 × 10^-2m

No. of turns, N = 2 × 500 = 1000

Current, I = 5A

To calculate:

The magnetic induction at its centre along the axis.

Magnetic Induction, B = ?

Formula:

B = μ_onI

Solution:

`"B"=mu_o("N"/"l")"I"`

`therefore"B"=(4pixx10^-7xx1000xx5)/3.142`

`therefore"B"=2xx10^-3 "T"`

Hence, the magnetic induction at the centre of the circular loop along its axis is 2 × 10^-3T.