A soft drink is available in two packs-(i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular base diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?
Solution
Given data is as follows:
(i) For tin can with rectangular base:
Length = 5 cm
Width = 4 cm
Height = 10 cm
(ii) For plastic cylinder with circular base
Diameter = 7 cm
Height = 10 cm
We have to find out which container has greater capacity and also the difference in their capacities.
(i) Volume of tin can = `"lenght" xx "breagth" xx "height"`
= `5xx4xx10`
=200 `cm^3`
(ii) Volume of cylinder = `pir^2h`
Diameter is given as 7cm. Therefore, r = `7/2`
Volume of cylinder = `22/7 xx 7/2xx7/2xx10`
= 385 cm3
From the above it can be concluded that plastic cylinder has greater capacity.
Difference in their capacities = 385 – 200 = 185 cm3
