A soft drink is available in two packs − (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

`["Assume "pi=22/7]`

#### Solution

The tin can will be cuboidal in shape while the plastic cylinder will be cylindrical in shape.

Length (*l*) of tin can = 5 cm

Breadth (*b*) of tin can = 4 cm

Height (*h*) of tin can = 15 cm

Capacity of tin can = *l × b* × *h*

= (5 × 4 × 15) cm^{3}

= 300 cm^{3}

Radius (*r*) of circular end of plastic cylinder = (7/2)cm = 3.5 cm

Height (*H*) of plastic cylinder = 10 cm

Capacity of plastic cylinder = π*r*^{2}*H*

`=[22/7xx(3.5)^2xx10]cm^3`

= (11 x 35) cm^{3}

= 385 cm^{3}

Therefore, plastic cylinder has the greater capacity.

Difference in capacity = (385 − 300) cm^{3 }= 85 cm^{3}