# A Small Town with a Demand of 1200 Kw of Electric Power at 220 V is Situated 20 Km Away from an Electric Plant Generating Power at 440 V. the Resistance of the Two Wirelines Carrying - Physics

A small town with a demand of 1200 kW of electric power at 220 V is situated 20 km away from an electric plant generating power at 440 V. The resistance of the two wirelines carrying power is 0.5 Ω per km. The town gets the power from the line through a 4000-220 V step-down transformer at a sub-station in the town. Estimate the line power loss in the form of heat.

#### Solution

Total electric power required,

P = 1200 kW = 1,200 xx 10^3 W

Supply voltage, V = 220 V
The voltage at which electric plant is generating power, V = 440 V
Distance between the town and power generating station, d = 20 km
The resistance of the two-wire lines carrying power  = 0.5  Ω/km
The total resistance of the wires, R = (20 + 20)0.5 = 20 Ω

A step-down transformer of rating 4000 - 220 V is used in the sub-station.

Input voltage, V1 = 4000 V
Output voltage, V2 = 220 V
Rms current in the wire lines is given as:

I = P/V_1 = (1200 xx 10^3)/4000 = 300 A

Line power loss = I^2R

= 300^2 xx 20

= 1800 xx 10^3W
= 1800 kW.

Concept: Peak and Rms Value of Alternating Current Or Voltage
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