A simple pendulum of frequency n falls freely under gravity from a certain height from the ground level. Its frequency of oscillation. - Physics

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MCQ

A simple pendulum of frequency n falls freely under gravity from a certain height from the ground level. Its frequency of oscillation.

Options

  • Remain unchanged

  • > n

  • Becomes zero

  • Becomes infinite

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Solution

Becomes zero

Explanation:

For free fall geff = 0, so frequency of oscillation will be zero

f = `1/(2π) sqrt("g"_"eff"/λ)`

f = 0

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