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A simple pendulum of frequency n falls freely under gravity from a certain height from the ground level. Its frequency of oscillation.

#### Options

Remain unchanged

> n

Becomes zero

Becomes infinite

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#### Solution

**Becomes zero**

**Explanation:**

For free fall g_{eff} = 0, so frequency of oscillation will be zero

f = `1/(2π) sqrt("g"_"eff"/λ)`

f = 0

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