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A simple pendulum is inside a spacecraft. What will be its periodic time?

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#### Solution

Periodic time of simple pendulum is given by, T = `2pisqrt("L"/"g")`

But, inside a spacecraft, acceleration due to gravity is zero.

∴ T = `2pisqrt("L"/0)`

∴ T = ∞

∴ The time period of a simple pendulum inside a spacecraft is infinite.

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