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A side of an isosceles right angled triangle is x. Find its hypotenuse.

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#### Solution

It is given that, a side of an isosceles right-angled triangle is x.

Then, the other side of the triangle is also x.

According to Pythagoras theorem.

\[\left( \text{Hypotenuse} \right)^2 = x^2 + x ^2 \]

\[ = 2 x^2 \]

\[ \therefore \text{Hypotenuse} = x\sqrt{2}\]

Hence, its hypotenuse is x\[\sqrt{2}\]

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