#### Question

A sector of a circle of radius 8cm contains the angle of 135°. Find the area of sector.

#### Solution

We know that the area A of a sector of an angle θ in the circle of radius r is given by `A=theta/360^@xxpi r^2`

It is given that r = 8 cm and θ = 135°.

Now we substitute the value of *r* and *θ* in above formula,

`A=135^@/360^@xxpixx8xx8 cm^2`

`=24 pi cm^2`

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#### APPEARS IN

Solution A Sector of a Circle of Radius 8cm Contains the Angle of 135°. Find the Area of Sector. Concept: Areas of Sector and Segment of a Circle.