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# A Scooter Weighing 150 Kg Together with Its Rider Moving at 36 Km/Hr is to Take a Turn of a Radius 30 M. What Horizontal Force on the Scooter is Needed to Make the Turn Possible ? - Physics

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ConceptCircular Motion

#### Question

A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of a radius 30 m. What horizontal force on the scooter is needed to make the turn possible ?

#### Solution

Given:
Mass = m = 150 kg
Speed = v = 36 km/hr = 10 m/s
Radius of turn = r = 30 m
Let the horizontal force needed to make the turn be F. We have :

$F = \frac{\text{mv}^2}{\text{r}} = \frac{150 \times (10 )^2}{30}$

$= \frac{150 \times 100}{30} = 500 \text{ N}$

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#### APPEARS IN

Solution A Scooter Weighing 150 Kg Together with Its Rider Moving at 36 Km/Hr is to Take a Turn of a Radius 30 M. What Horizontal Force on the Scooter is Needed to Make the Turn Possible ? Concept: Circular Motion.
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