Numerical

A sample of HCI gas is placed in an electric field of 2.5 × 10^{4} NC^{−1}. The dipole moment of each HCI molecule is 3.4 × 10^{−30} Cm. Find the maximum torque that can act on a molecule.

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#### Solution

Given:

Electric field intensity, *E = *2.5 × 10^{4} NC^{−1}

Dipole moment of an HCl molecule,* P* = 3.4 × 10^{−30} Cm

Torque on the molecule,

\[\Gamma = PE\sin\theta\]

For

\[\Gamma_{max}\] , putting sin

*θ*= 1, we get\[\Gamma_{max} = PE\]

\[ = 3 . 4 \times {10}^{- 30} 2 . 5 \times {10}^4 \]

\[ = 8 . 5 \times {10}^{- 26} \] Nm

Concept: Electric Dipole

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