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A Rubber Company is Engaged in Producing Three Types of Tyres A, B and C. Each Type Requires Processing in Two Plants, Plant I and Plant Ii. the Capacities of the Two Plants. - Mathematics

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A rubber company is engaged in producing three types of tyres AB and C. Each type requires processing in two plants, Plant I and Plant II. The capacities of the two plants, in number of tyres per day, are as follows:

Plant A B C
I 50 100 100
II 60 60 200

The monthly demand for tyre AB and C is 2500, 3000 and 7000 respectively. If plant I costs Rs 2500 per day, and plant II costs Rs 3500 per day to operate, how many days should each be run per month to minimize cost while meeting the demand? Formulate the problem as LPP.

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Solution

Let plant I be run for days and plant II be run for days

Then,

Tyres Plant I  (x)     Plant II (y) Demand
A 50 60 2500
B 100 60 3000
C 100 200 7000

Minimum demand for Tyres A,B and C is 2500, 3000 and 7000 respectively.The demand can be more than the minimum demand.
Therefore,the inequations will be

\[50x + 60y \geq 2500\]
\[100x + 60y \geq 3000\] 

\[100x + 200y \geq 7000\]

Also, the objective function is   Z = 2500x + 3500y

Hence, the required LPP is as follows:

Minimise Z = 2500x + 3500y

subject to 

\[50x + 60y \geq 2500\]
\[100x + 60y \geq 3000\]

\[100x + 200y \geq 7000\]

Concept: Introduction of Linear Programming
  Is there an error in this question or solution?

APPEARS IN

RD Sharma Class 12 Maths
Chapter 30 Linear programming
Exercise 30.1 | Q 5 | Page 15

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