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A Roller of Diameter 0.9 M and the Length 1.8 M is Used to Press the Ground. Find the Area of the Ground Pressed by It in 500 Revolutions.(Pi=3.14) - Geometry

Sum

A roller of diameter 0.9 m and the length 1.8 m is used to press the ground. Find the area of the ground pressed by it in 500 revolutions.
`(pi=3.14)`

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Solution

Diameter = 0.9 m  r = 0.45 m

Height =1.8 m

Number of rotations = 500

Area of the ground pressed by the roller in one rotation = curved surface area of the roller.

= `2pi "rh"`

= 2 × 3.14 × 0.45 × 1.8

= 5.0868 m2

 Area of the ground pressed by the roller in 500 rotations.

= 500 × 5.0868 m2

= 2543.4 m2

 Area of the ground pressed by the roller is 2543.4 m2

Concept: Properties of Ratios of Areas of Two Triangles
  Is there an error in this question or solution?
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