Advertisement Remove all ads

A Regular Hexagon of Side 10 Cm Has a Charge 5 µC at Each of Its Vertices. Calculate the Potential at the Centre of the Hexagon. - Physics

A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon.

Advertisement Remove all ads


The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.


Charge, q = 5 µC = 5 × 10−6 C

Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm

Distance of each vertex from centre O, d = 10 cm

Electric potential at point O,



`in_0`= Permittivity of free space

`1/(4piin_0)=9xx10^9 NC^-2 m^-2

`therefore V=(6xx9xx10^9xx5xx10^-6)/0.1`

`=2.7xx10^6 V`

Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.

Concept: Potential Energy of a System of Charges
  Is there an error in this question or solution?
Advertisement Remove all ads


NCERT Class 12 Physics Textbook
Chapter 2 Electrostatic Potential and Capacitance
Q 2 | Page 87
Advertisement Remove all ads
Advertisement Remove all ads

View all notifications

      Forgot password?
View in app×