A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon.
The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.
Charge, q = 5 µC = 5 × 10−6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O, d = 10 cm
Electric potential at point O,
`in_0`= Permittivity of free space
`1/(4piin_0)=9xx10^9 NC^-2 m^-2
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.