Advertisement Remove all ads

# A Rectangular Field is 70 M Long and 60 M Broad. a Well of Dimensions 14 M × 8 M × 6 M is Dug Outside the Field and the Earth Dug-out from this Well is Spread Evenly on the Field. How Much - Mathematics

Answer in Brief

A rectangular field is 70 m long and 60 m broad. A well of dimensions 14 m × 8 m × 6 m is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

Advertisement Remove all ads

#### Solution

$\text { Dimension of the well = 14 m } \times 8 m \times 6 m$

$\text { The volume of the dug - out earth = 14 }\times 8 \times 6 = 672 m^3$

$\text { Now, we will spread this dug - out earth on a field whose length, breadth and height are 70 m, 60 m and h m, respectively } .$

$\text { Volume of the dug - out earth = length } \times \text { breadth }\times \text { height }= 70 \times 60 \times h$

$\Rightarrow 672 = 4200 \times h$

$\Rightarrow h = \frac{672}{4200} = 0 . 16 m$

$\text { We know that 1 m = 100 cm }$

$\therefore \text { The earth level will rise by 0 . 16 m = 0 . 16 } \times 100 cm = 16 cm .$

Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.2 | Q 13 | Page 15
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?
Course