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A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled? - Chemistry

A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled?

 

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Solution

When the concentrations of both A and B are doubled,

`-(d[R])/dt = k [A][B]^2`

`= k[2A][2B]^2`

`=8.k[A][B]^2`

Therefore, the rate of reaction will increase 8 times.

Concept: Integrated Rate Equations - First Order Reactions
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APPEARS IN

NCERT Class 12 Chemistry Textbook
Chapter 4 Chemical Kinetics
Q 9.3 | Page 118
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