Maharashtra State BoardHSC Commerce 12th Board Exam
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A random variable X has the following probability distribution:Determine P(X > 4) - Mathematics and Statistics

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Sum

A random variable X has the following probability distribution:

x 1 2 3 4 5 6 7
P(x) k 2k 2k 3k k2 2k2 7k2 + k

Determine P(X > 4)

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Solution

P(X > 4)

= P(X = 5 or X = 6 or X = 7)

= P(X = 5) + P(X = 6) + P(X = 7)

= k2 + 2k2 + 7k2 + k

= 10k2 + k

= `10(1/10)^2 + (1)/(10)`

= `(1)/(10) + (1)/(10)`

= `(1)/(5)`

Concept: Random Variables and Its Probability Distributions
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